b^2-2b-5=-2

Solution for b^2-2b-5=-2 equation:

Simplifying
b2 + -2b + -5 = -2

Reorder the terms:
-5 + -2b + b2 = -2

Solving
-5 + -2b + b2 = -2

Solving for variable 'b'.

Reorder the terms:
-5 + 2 + -2b + b2 = -2 + 2

Combine like terms: -5 + 2 = -3
-3 + -2b + b2 = -2 + 2

Combine like terms: -2 + 2 = 0
-3 + -2b + b2 = 0

Factor a trinomial.
(-1 + -1b)(3 + -1b) = 0

Subproblem 1
Set the factor '(-1 + -1b)' equal to zero and attempt to solve:

Simplifying
-1 + -1b = 0

Solving
-1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = 0 + 1
-1b = 0 + 1

Combine like terms: 0 + 1 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1
Subproblem 2
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Solution
b = {-1, 3}